Calculate the T Statistic for Testing Equality of Means Where

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The Answer is

\bar { X } _ { 1 }

= 8.2,

\bar { X } _ { 2 }

= 11.3,s₁² = 5.4,s₂² = 5.2,n₁ = 6,and n₂ = 7.(Assume equal population variances. )
-2.42
Feedback:s² = ((6 - 1)(5.4)+ (7 - 1)(5.2))/(6 + 7 - 2)= 5.291
s = √[5.291(1/6 + 1/7)] = 1.2797
t = (8.2 - 11.3)/1.2797 = -2.42

Calculate the T Statistic for Testing Equality of Means Where

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