Dinitrogen Tetroxide (N₂O₄) Decomposes to Nitrogen Dioxide (NO₂) $\Delta$ H° = 5802 KJ/mol And Decomposes

question 64

Multiple Choice

Dinitrogen tetroxide (N₂O₄) decomposes to nitrogen dioxide (NO₂) . If $\Delta$ H° = 58.02 kJ/mol and $\Delta$ S° = 176.1 J/mol · K, at what temperature are reactants and products in their standard states at equilibrium?

• A) +56.5°C
• B) +329.5°C
• C) -272.7°C
• D) +25.0°C
• E) +98.3°C

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