Maximize$p = x + 2 y$ Subject To$$\begin{aligned}
x + y & \leq 20 \
y & \geq 8 \
2 x - y & \geq 0 \
x \geq 0 , y & \geq 0
\end{aligned}$$

Question

Examlex · Accepted Answer

The Answer of Maximize$p = x + 2 y$ Subject To$$\begin{aligned}
x + y & \leq 20 \
y & \geq 8 \
2 x - y & \geq 0 \
x \geq 0 , y & \geq 0
\end{aligned}$$

Maximize $p = x + 2 y$ Subject To $\begin{aligned}x + y & \leq 20 \\y & \geq 8 \\2 x - y & \geq 0 \\x \geq 0 , y & \geq 0\end{aligned}$

Definitions:

Maximize p=x+2yp = x + 2 yp=x+2y Subject To x+y≤20y≥82x−y≥0x≥0,y≥0\begin{aligned}x + y & \leq 20 \\y & \geq 8 \\2 x - y & \geq 0 \\x \geq 0 , y & \geq 0\end{aligned}x+yy2x−yx≥0,y​≤20≥8≥0≥0​

Definitions:

Maximize $p = x + 2 y$ Subject To $\begin{aligned}x + y & \leq 20 \\y & \geq 8 \\2 x - y & \geq 0 \\x \geq 0 , y & \geq 0\end{aligned}$