Maximize$p = 12 x + 10 y$ Subject To$$\begin{aligned}
x + y & \leq 40 \
x & \geq 1 \
- x + 2 y & \geq 0 \
x \geq 0 , y & \geq 0
\end{aligned}$$

Question

Examlex · Accepted Answer

The Answer of Maximize$p = 12 x + 10 y$ Subject To$$\begin{aligned}
x + y & \leq 40 \
x & \geq 1 \
- x + 2 y & \geq 0 \
x \geq 0 , y & \geq 0
\end{aligned}$$

Maximize $p = 12 x + 10 y$ Subject To $\begin{aligned}x + y & \leq 40 \\x & \geq 1 \\- x + 2 y & \geq 0 \\x \geq 0 , y & \geq 0\end{aligned}$

Definitions:

Maximize p=12x+10yp = 12 x + 10 yp=12x+10y Subject To x+y≤40x≥1−x+2y≥0x≥0,y≥0\begin{aligned}x + y & \leq 40 \\x & \geq 1 \\- x + 2 y & \geq 0 \\x \geq 0 , y & \geq 0\end{aligned}x+yx−x+2yx≥0,y​≤40≥1≥0≥0​

Definitions:

Maximize $p = 12 x + 10 y$ Subject To $\begin{aligned}x + y & \leq 40 \\x & \geq 1 \\- x + 2 y & \geq 0 \\x \geq 0 , y & \geq 0\end{aligned}$