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Model the Curve with a Sine Function P=15P = \frac { 1 } { 5 }

question 40

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Model the curve with a sine function.
 Model the curve with a sine function.        Note that the period of the curve is  P = \frac { 1 } { 5 }  and its range is  [ - 2.2,2.2 ]  and the graph of the sine function is shifted to the left 0.55 units.   A)   f ( x )  = 2.2 \sin ( 10 \pi ( x + 0.55 )  )   B)   f ( x )  = 2.2 \sin ( 10 \pi ( x - 0.55 )  )   C)   f ( x )  = 2.2 \sin ( 10 \pi x + 0.55 )   D)   f ( x )  = 2.2 \sin ( 10 \pi ( 2 x + 0.55 )  )   E)   f ( x )  = 4.4 \sin ( 5 \pi ( x + 0.55 )  )
Note that the period of the curve is P=15P = \frac { 1 } { 5 } and its range is [2.2,2.2][ - 2.2,2.2 ] and the graph of the sine function is shifted to the left 0.55 units.


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