Calculate $\frac { \partial ^ { 2 } f } { \partial x ^ { 2 } }$

question 15

Multiple Choice

Calculate $\frac { \partial ^ { 2 } f } { \partial x ^ { 2 } }$ , $\frac { \partial ^ { 2 } f } { \partial y x }$ when defined. $f ( x , y ) = 4 x ^ { 0.9 } y ^ { 0.7 }$

• A) \(\frac { \partial ^ { 2 } f } { \partial x ^ { 2 } } = - 0.36 y ^ { 0.7 } x ^ { - 1.1 }\) , \(\frac { \partial ^ { 2 } f } { \partial y x } = - 2.52 y ^ { 0.3 } x ^ { 0.1 }\)
• B) \(\frac { \partial ^ { 2 } f } { \partial x ^ { 2 } } = - 3.6 y ^ { 0.7 } x ^ { - 0.1 }\) , \(\frac { \partial ^ { 2 } f } { \partial y x } = 2.8 y ^ { - 0.3 } x ^ { 0.9 }\)
• C) \(\frac { \partial ^ { 2 } f } { \partial x ^ { 2 } } = - 3.6 y ^ { 0.7 } x ^ { - 1.1 }\) , \(\frac { \partial ^ { 2 } f } { \partial y x } = 3.6 y ^ { - 0.3 } x ^ { - 0.1 }\)
• D) \(\frac { \partial ^ { 2 } f } { \partial x ^ { 2 } } = - 0.36 y ^ { 0.7 } x ^ { - 1.1 }\) , \(\frac { \partial ^ { 2 } f } { \partial y x } = 2.52 y ^ { - 0.3 } x ^ { - 0.1 }\)
• E) \(\frac { \partial ^ { 2 } f } { \partial x ^ { 2 } } = - 4 y ^ { - 0.3 } x ^ { - 1.1 }\) , \(\frac { \partial ^ { 2 } f } { \partial y x } = 4 y ^ { - 1.3 } x ^ { - 0.1 }\)

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