The Upper Limit of a 95% Confidence Interval for the Variance

question 46

Multiple Choice

The upper limit of a 95% confidence interval for the variance $\sigma ^ { 2 }$ of a normal population using a sample of size n and variance value $s ^ { 2 }$ is given by:

• A) \(( n - 1 ) s ^ { 2 } / \chi _ { .05 , { n - 1 } } ^ { 2 }\)
• B) \(( n - 1 ) s ^ { 2 } / \chi _ { .015 , n - 1 } ^ { 2 }\)
• C) \(( n - 1 ) s ^ { 2 } / \chi _ {.95 ,{ n - 1 } } ^ { 2 }\)
• D) \(( n - 1 ) s ^ { 2 } / \chi ^ { 2 } _{.975 , n - 1}\)
• E) None of the above answers are correct.