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The Goal Programming Problem Below Was Solved with the Management \ge

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The goal programming problem below was solved with the Management Scientist.
Min
P1(d1-) + P2(d2+) + P3(d3-)
s.t.
72x1 + 38x2 + 23x3 - 20,000
.72x1 -.76x2 - .23x3 + d1- - d1+ = 0
x3 + d2- - d2+ = 150
38x2 + d3- -d3+ = 2000
x1, x2, x3, d1-, d 1+, d2-, d2+, d3-, d3+ \ge 0
Partial output from three successive linear programming problems is given. For each problem, give the original objective function expression and its value, and list any constraints needed beyond those that were in the original problem.  a. Objective Function Value =0.000 Variable  Value  Reduced Cost  D1MINUS 0.0001.000 X1 52.6320.000 X2 0.0000.000 X3 150.0000.000 D1PLUS 3.3950.000 D2MINUS 0.0000.000 D2PLUS 0.0000.000 D3MINUS 0.0000.000 D3PLUS 0.0000.000\begin{array}{l}\text { a. Objective Function Value } = 0.000\\\begin{array} { l c c } \text { Variable } & \text { Value } & \text { Reduced Cost } \\\text { D1MINUS } & 0.000 & 1.000 \\\text { X1 } & 52.632 & 0.000 \\\text { X2 } & 0.000 & 0.000 \\\text { X3 } & 150.000 & 0.000 \\\text { D1PLUS } & 3.395 & 0.000 \\\text { D2MINUS } & 0.000 & 0.000 \\\text { D2PLUS } & 0.000 & 0.000 \\\text { D3MINUS } & 0.000 & 0.000 \\\text { D3PLUS } & 0.000 & 0.000\end{array}\end{array}  b. Objective Function Value =0.000 Variable  Value  Reduced Cost  D2PLUS 0.0001.000 X1 52.6320.000 X2 0.0000.000 X3 150.0000.000 D1MINUS 0.0000.000 D1PLUS 3.3950.000 D2MINUS 0.0000.000 D3MINUS 0.0000.000 D3PLUS 0.0000.000\begin{array}{l}\text { b. Objective Function Value } = 0.000\\\begin{array} { l c c } \text { Variable } & \text { Value } & \text { Reduced Cost } \\\text { D2PLUS } & 0.000 & 1.000 \\\text { X1 } & 52.632 & 0.000 \\\text { X2 } & 0.000 & 0.000 \\\text { X3 } & 150.000 & 0.000 \\\text { D1MINUS } & 0.000 & 0.000 \\\text { D1PLUS } & 3.395 & 0.000 \\\text { D2MINUS } & 0.000 & 0.000 \\\text { D3MINUS } & 0.000 & 0.000 \\\text { D3PLUS } & 0.000 & 0.000\end{array}\end{array}  c. Objective Function Value =0.000 Variable  Value  Reduced Cost  D3MINUS 0.0001.000 X1 52.6320.000 X2 0.0000.000 X3 150.0000.000 D1MINUS 0.0000.000 D1PLUS 3.3950.000 D2MINUS 0.0000.000 D2PLUS 0.0000.000 D3PLUS 0.0000.000\begin{array}{l}\text { c. Objective Function Value } = 0.000\\\begin{array} { l c c } \text { Variable } & \text { Value } & \text { Reduced Cost } \\\text { D3MINUS } & 0.000 & 1.000 \\\text { X1 } & 52.632 & 0.000 \\\text { X2 } & 0.000 & 0.000 \\\text { X3 } & 150.000 & 0.000 \\\text { D1MINUS } & 0.000 & 0.000 \\\text { D1PLUS } & 3.395 & 0.000 \\\text { D2MINUS } & 0.000 & 0.000 \\\text { D2PLUS } & 0.000 & 0.000 \\\text { D3PLUS } & 0.000 & 0.000\end{array}\end{array}


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