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Taylor Used a Regular Hexagonal Stock with a 2-In 5.196in25.196 \mathrm { in } ^ { 2 }

question 11

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Taylor used a regular hexagonal stock with a 2-in. distance across the flats to mill a new hexagonal rod as illustrated in the cross-section. Assume the vertices of the inside hexagon are the midpoints of the original hexagon's sides. What is the area milled off the original hexagon to create the new one?  Taylor used a regular hexagonal stock with a 2-in. distance across the flats to mill a new hexagonal rod as illustrated in the cross-section. Assume the vertices of the inside hexagon are the midpoints of the original hexagon's sides. What is the area milled off the original hexagon to create the new one?    A)   5.196 \mathrm { in } ^ { 2 }  B)   0.137 \mathrm { in } ^ { 2 }  C)   0.866 \mathrm { in } ^ { 2 }  D)   2.598 \mathrm { in } ^ { 2 }


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