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A Block of Mass M Is Suspended by Two Strings θ\theta

question 17

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   A block of mass m is suspended by two strings and is in equilibrium as suggested in the figure above. The tension of the right-hand string divided by the tension of the left-hand string is given by A)  sin  \theta <sub>2</sub> / sin  \theta <sub>1</sub>.<sub> </sub> B)  cos \theta <sub>1</sub> / cos  \theta <sub>2</sub>.<sub> </sub> C)  cos  \theta <sub>2 </sub>/ cos  \theta <sub>1</sub>. D)  sin  \theta <sub>1</sub> / sin  \theta <sub>2</sub>. E)  mg  \theta T<sub>1</sub> sin  \theta <sub>1</sub>)  / T<sub>1</sub> sin  \theta <sub>2</sub>) . A block of mass m is suspended by two strings and is in equilibrium as suggested in the figure above. The tension of the right-hand string divided by the tension of the left-hand string is given by


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