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If the Random Variable X Is Exponentially Distributed with Parameter λ\lambda

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Short Answer

If the random variable X is exponentially distributed with parameter λ\lambda = 1.75, then P(1.5 \le X \le 3.8), up to 4 decimal places, is:  A. 0.0711. B. 0.0473. C. 0.1184. D. 0.4739\begin{array}{|l|l|}\hline\text { A. } & 0.0711 . \\\hline \text { B. } & 0.0473 . \\\hline \text { C. } & 0.1184 . \\\hline \text { D. } & 0.4739 \\\hline\end{array}


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