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The Iodine "Clock Reaction" Involves the Following Sequence of Reactions \rightarrow

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The iodine "clock reaction" involves the following sequence of reactions occurring in a reaction mixture in a single beaker.
1. IO3¯(aq) + 5I¯(aq) + 6H+(aq) \rightarrow 3I2(aq) + 3H2O(l)
2. I2(aq) + 2S2O32¯(aq) \rightarrow 2I¯(aq) + S4O62¯(aq)
The molecular iodine (I2) formed in reaction 1 is immediately used up in reaction 2, so that no iodine accumulates. In one experiment, a student made up a reaction mixture which initially contained 0.0020 mol of iodate ions (IO3¯) . If the iodate ions reacted completely, how many moles of thiosulfate ions (S2O32¯) were needed in reaction 2, in order to react completely with the iodine (I2) produced in reaction 1?

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