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The Goal Programming Problem Below Was Solved with the Management

question 2

Essay

The goal programming problem below was solved with the Management Scientist.
Min
P1(d1−) + P2(d2+) + P3(d3−)
s.t.
72x1 + 38x2 + 23x3 ≤ 20,000
.72x1 − .76x2 − .23x3 + d1− − d1+ = 0
x3 + d2− − d2+ = 150
38x2 + d3− − d3+ = 2000
x1, x2, x3, d1−, d 1+, d2−, d2+, d3−, d3+ ≥ 0
Partial output from three successive linear programming problems is given. For each problem, give the original objective function expression and its value, and list any constraints needed beyond those that were in the original problem. The goal programming problem below was solved with the Management Scientist. Min P<sub>1</sub>(d<sub>1</sub>−) + P<sub>2</sub>(d<sub>2</sub><sup>+</sup>) + P<sub>3</sub>(d<sub>3</sub>−) s.t. 72x<sub>1</sub> + 38x<sub>2</sub> + 23x<sub>3</sub> ≤ 20,000 .72x<sub>1</sub> − .76x<sub>2</sub> − .23x<sub>3</sub> + d<sub>1</sub>− − d<sub>1</sub><sup>+</sup> = 0 x<sub>3</sub> + d<sub>2</sub>− − d<sub>2</sub><sup>+</sup> = 150 38x<sub>2</sub> + d<sub>3</sub>− − d<sub>3</sub><sup>+</sup> = 2000 x<sub>1</sub>, x<sub>2</sub>, x<sub>3</sub>, d<sub>1</sub>−, d <sub>1</sub><sup>+</sup>, d<sub>2</sub>−, d<sub>2</sub><sup>+</sup>, d<sub>3</sub>−, d<sub>3</sub><sup>+</sup> ≥ 0 Partial output from three successive linear programming problems is given. For each problem, give the original objective function expression and its value, and list any constraints needed beyond those that were in the original problem.   ​   ​  The goal programming problem below was solved with the Management Scientist. Min P<sub>1</sub>(d<sub>1</sub>−) + P<sub>2</sub>(d<sub>2</sub><sup>+</sup>) + P<sub>3</sub>(d<sub>3</sub>−) s.t. 72x<sub>1</sub> + 38x<sub>2</sub> + 23x<sub>3</sub> ≤ 20,000 .72x<sub>1</sub> − .76x<sub>2</sub> − .23x<sub>3</sub> + d<sub>1</sub>− − d<sub>1</sub><sup>+</sup> = 0 x<sub>3</sub> + d<sub>2</sub>− − d<sub>2</sub><sup>+</sup> = 150 38x<sub>2</sub> + d<sub>3</sub>− − d<sub>3</sub><sup>+</sup> = 2000 x<sub>1</sub>, x<sub>2</sub>, x<sub>3</sub>, d<sub>1</sub>−, d <sub>1</sub><sup>+</sup>, d<sub>2</sub>−, d<sub>2</sub><sup>+</sup>, d<sub>3</sub>−, d<sub>3</sub><sup>+</sup> ≥ 0 Partial output from three successive linear programming problems is given. For each problem, give the original objective function expression and its value, and list any constraints needed beyond those that were in the original problem.   ​   ​  The goal programming problem below was solved with the Management Scientist. Min P<sub>1</sub>(d<sub>1</sub>−) + P<sub>2</sub>(d<sub>2</sub><sup>+</sup>) + P<sub>3</sub>(d<sub>3</sub>−) s.t. 72x<sub>1</sub> + 38x<sub>2</sub> + 23x<sub>3</sub> ≤ 20,000 .72x<sub>1</sub> − .76x<sub>2</sub> − .23x<sub>3</sub> + d<sub>1</sub>− − d<sub>1</sub><sup>+</sup> = 0 x<sub>3</sub> + d<sub>2</sub>− − d<sub>2</sub><sup>+</sup> = 150 38x<sub>2</sub> + d<sub>3</sub>− − d<sub>3</sub><sup>+</sup> = 2000 x<sub>1</sub>, x<sub>2</sub>, x<sub>3</sub>, d<sub>1</sub>−, d <sub>1</sub><sup>+</sup>, d<sub>2</sub>−, d<sub>2</sub><sup>+</sup>, d<sub>3</sub>−, d<sub>3</sub><sup>+</sup> ≥ 0 Partial output from three successive linear programming problems is given. For each problem, give the original objective function expression and its value, and list any constraints needed beyond those that were in the original problem.   ​   ​


Definitions:

WACC

The Weighted Average Cost of Capital represents a formula used to assess a company's cost of capital, with each type of capital being weighted according to its proportion.

Discount Rate

The interest rate used in discounted cash flow analysis to determine the present value of future cash flows or to discount a future investment.

Risk Class

Categories of assets or investments grouped together based on the level of risk and return characteristics they possess.

Cost of Equity

The theoretical disbursement a firm makes to its equity stakeholders as remuneration for the risk they bear by putting their capital into the business.

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