The Energy Change for an Electronic Transition in a One-Electron $\left(-2.178 \times 10^{-18} \mathrm{~J}\right) Z^{2}\left(\frac{1}{n_{\text {final }} 2}-\frac{1}{n_{\text {initial }} 2}\right)$

question 104

Multiple Choice

The energy change for an electronic transition in a one-electron atom or ion H, He⁺, Li²⁺, etc.) from n _initial to n _final Is given by $\left(-2.178 \times 10^{-18} \mathrm{~J}\right) Z^{2}\left(\frac{1}{n_{\text {final }} 2}-\frac{1}{n_{\text {initial }} 2}\right)$ where Z is the atomic number.How much energy is required to ionize a ground-state Li²⁺ion (n_final = $\infty$ ) ?

• A)2.18 *10^-18 J
• B)4.36 * 10^-18 J
• C)1.96 * 10^-17 J
• D)1.09 *10^-18 J
• E)5.45 * 10^-19 J

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