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Consider the Curve r(t)=(2t2+1)i+(t2+1)j+tk\vec { r } ( t ) = \left( 2 t ^ { 2 } + 1 \right) \vec { i } + \left( t ^ { 2 } + 1 \right) \vec { j } + t \vec { k }

question 19

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Consider the curve r(t)=(2t2+1)i+(t2+1)j+tk\vec { r } ( t ) = \left( 2 t ^ { 2 } + 1 \right) \vec { i } + \left( t ^ { 2 } + 1 \right) \vec { j } + t \vec { k } Does the curve lie on the parametric surface x=s2+t2,y=s2,z=t?x = s ^ { 2 } + t ^ { 2 } , y = s ^ { 2 } , z = t ?


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