Solve $\frac { d y } { d t } = y ^ { 2 } + 1$

question 43

Multiple Choice

Solve $\frac { d y } { d t } = y ^ { 2 } + 1$ if y = 1 when t = 0.

• A) \(y = \arctan \left( t + \frac { \pi } { 4 } \right)\)
• B) \(y = \arctan \left( t - \frac { \pi } { 4 } \right)\)
• C) \(y = \tan \left( t + \frac { \pi } { 4 } \right)\)
• D) \(y = \tan \left( t - \frac { \pi } { 4 } \right)\)

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