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In an Electric Circuit, Let Q(t)be the Charge on a Capacitor

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In an electric circuit, let Q(t) be the charge on a capacitor at time t.Then the current in the circuit is given by I(t) =dQdtI(t) =\frac{d Q}{d t} (the rate of change of the charge) .The charge and the current satisfy the differential equation LdIdt+QC=0L \frac{d I}{d t}+\frac{Q}{C}=0 .If L = 34 henry, and C = 10 farad, find a formula for Q(t) with initial conditions Q(0) = 0 and I(0) = 2.Round constants to three decimal places.


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