Cesium 137 (Cs¹³⁷)is a Short-Lived Radioactive Isotope $e^{-\left(\frac{\ln 2}{30}\right) t}$

question 37

Multiple Choice

Cesium 137 (Cs¹³⁷) is a short-lived radioactive isotope.It decays at a rate proportional to the amount of itself present and has a half-life of 30 years (i.e., the amount of Cs¹³⁷ remaining t years after A₀ mg of the radioactive isotope is released is given by $e^{-\left(\frac{\ln 2}{30}\right) t}$ ) .As a result of its operations, a nuclear power plant releases Cs¹³⁷ at a rate of 0.12 mg per year.The plant began its operations in 1990, which we will designate as t = 0.Assume there is no other source of this particular isotope.Which of the following differential equations have a solution R(t) , the amount (in mg) of Cs¹³⁷ in t years? (We are assuming R(0) = 0.)

• A) \(\frac{d R}{d t}=0.12+e^{-\left(\frac{\ln 2}{30}\right) R}\)
• B) \(\frac{d R}{d t}=0.12-e^{-\left(\frac{\ln 2}{30}\right)}+R\)
• C) \(\frac{d R}{d t}=0.12-\frac{\ln 2}{30} R\)
• D) \(\frac{d R}{d t}=0.12 R-\frac{\ln 2}{30}\)

Distinguish between different types of costs and their treatment in manufacturing accounts.

Learn the appropriate journal entries for various manufacturing and costing transactions.

Recognize the implications of closing out overapplied or underapplied manufacturing overhead.

Understand the application and impact of manufacturing overhead on product costs.

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