$\int \frac{3 e^{3 x}}{1+e^{6 x}} d x=\tan ^{-1}\left(e^{3 x}\right)+C$

question 128

True/False

$\int \frac{3 e^{3 x}}{1+e^{6 x}} d x=\tan ^{-1}\left(e^{3 x}\right)+C$ .

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