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If F(z)=tan6zlnzF ( z ) = \frac { \tan 6 z } { \ln z }

question 95

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If F(z)=tan6zlnzF ( z ) = \frac { \tan 6 z } { \ln z } , then F(z)=6cos2zlnz(tan6z)1z(lnz)2F ^ { \prime } ( z ) = \frac { \frac { 6 } { \cos ^ { 2 } z } \ln z - ( \tan 6 z ) \frac { 1 } { z } } { ( \ln z ) ^ { 2 } } .


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