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If R(θ)=θcos(θ6)R ( \theta ) = \sqrt { \theta } \cos \left( \theta ^ { 6 } \right)

question 151

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If R(θ)=θcos(θ6)R ( \theta ) = \sqrt { \theta } \cos \left( \theta ^ { 6 } \right) , then R(θ)=12θcos(θ6)+θ6θ5sin(θ6)R ^ { \prime } ( \theta ) = \frac { 1 } { 2 \sqrt { \theta } } \cos \left( \theta ^ { 6 } \right) + \sqrt { \theta } \cdot 6 \theta ^ { 5 } \sin \left( \theta ^ { 6 } \right) .


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