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Use the substitution method to solve the system.
-6x + 5y = -12 -4x - 2y = 0
Q1: <span class="ql-formula" data-value="25 x ^ { 2
Q3: <span class="ql-formula" data-value="f ( x ) =
Q25: <span class="ql-formula" data-value="\log _ { 7 }
Q25: <span class="ql-formula" data-value="2 ^ { - 4
Q64: <span class="ql-formula" data-value="\begin{array}{l}3 x-2 y \leq 6
Q71: <span class="ql-formula" data-value="( 5 a ) ^
Q77: <span class="ql-formula" data-value="\log _ { 5 }
Q106: <span class="ql-formula" data-value="3 x ^ { 2
Q107: <span class="ql-formula" data-value="- 6 x ^ {
Q181: <span class="ql-formula" data-value="25 x + 15 >