Solve for X $0.3 \%$ Annually If There Were $5,226,000$ Residents in the City in 2008 , Find How Many

question 13

Multiple Choice

Solve for x.
-A city is growing at the rate of $0.3 \%$ annually. If there were $5,226,000$ residents in the city in 2008 , find how many (to the nearest ten-thousand) are living in that city in 2012 . Use $y = 5,226,000 ( 2.7 ) ^ { 0.003 t }$ .

• A) \(5,290,000\)
• B) \(5,320,000\)
• C) \(14,110,000\)
• D) 170,000

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