Rewrite the Equation in Standard Form $$x ^ { 2 } + y ^ { 2 } + 14 y + 40 = 0$$

question 54

Multiple Choice

Rewrite the equation in standard form. Find the center and radius of the circle.
- $$x ^ { 2 } + y ^ { 2 } + 14 y + 40 = 0$$

• A) \(( x + 7 ) ^ { 2 } + y ^ { 2 } = 9\)
• center \(( - 7,0 ) , \mathrm { r } = 3\)
• B) \(x ^ { 2 } + ( y + 7 ) ^ { 2 } = 9\)
• center \(( 0 , - 7 ) , r = 3\)
• C) \(x ^ { 2 } + ( y - 7 ) ^ { 2 } = 9\)
• center \(( 0,7 ) , \mathrm { r } = 3\)
• D) \(x ^ { 2 } + ( y + 7 ) ^ { 2 } = 9\)
• center \(( 0,7 ) , r = 3\)

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