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Find the Maximum Value Of Q(x)Q ( x ) Subject to the Constraints

question 12

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Find the maximum value of Q(x) Q ( x ) subject to the constraints xTx=1_x T _ { x } = 1 and xTu=0_x { T } \mathbf { _u } = 0 , where uu is a unit eigenvector corresponding to the greatest eigenvalue of the matrix of the quadratic form.
- Q(x) =3x12+8x22+4x23Q ( x ) = 3 x { } _ { 1 } ^ { 2 } + 8 x { } _ { 2 } ^ { 2 } + 4x \frac { 2 } { 3 }


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