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Consider the Difference Equation xk+1=Axk\mathbf { x } _ { \mathbf { k } + 1 } = \mathrm { Ax } _ { \mathbf { k } }

question 7

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Consider the difference equation xk+1=Axk\mathbf { x } _ { \mathbf { k } + 1 } = \mathrm { Ax } _ { \mathbf { k } } , where A\mathrm { A } has eigenvalues and corresponding eigenvectors v1\mathbf { v } _ { 1 } , v2\mathbf { v } _ { 2 } , and v3\mathbf { v } _ { 3 } given below. Find the general solution of this difference equation if x0x _ { 0 } is given as below.

- λ1=1.3,λ2=0.8,λ3=0.6,v1=[661],v2=[212],v3=[122]\lambda _ { 1 } = 1.3 , \lambda _ { 2 } = 0.8 , \lambda _ { 3 } = 0.6 , \mathbf { v } _ { 1 } = \left[ \begin{array} { r } - 6 \\ 6 \\ 1 \end{array} \right] , \mathbf { v } _ { 2 } = \left[ \begin{array} { l } 2 \\ 1 \\ 2 \end{array} \right] , \mathbf { v } _ { 3 } = \left[ \begin{array} { r } 1 \\ 2 \\ - 2 \end{array} \right] , and x0=[33337]\mathbf { x } _ { 0 } = \left[ \begin{array} { r } - 33 \\ 33 \\ - 7 \end{array} \right]


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