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The Sum of the Squares of the First N (2n1)(2n)(2n+1)6\frac{(2 n-1)(2 n)(2 n+1)}{6}

question 59

Multiple Choice

The sum of the squares of the first n positive odd integers is (2n1) (2n) (2n+1) 6\frac{(2 n-1) (2 n) (2 n+1) }{6}
Use this expression to find the sum 12+32+52++7521^{2}+3^{2}+5^{2}+\cdots+75^{2}


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