After Translation of Coordinate Axes, a Quadratic
Equation Becomes $\frac{\left(x^{\prime}\right)^{2}}{16}+\frac{\left(y^{\prime}\right)^{2}}{9}=1$ Had the Effect of Moving the Point (X, Y)=(1,-2)

question 8

Multiple Choice

After translation of coordinate axes, a quadratic
equation becomes $\frac{\left(x^{\prime}\right) ^{2}}{16}+\frac{\left(y^{\prime}\right) ^{2}}{9}=1$
had the effect of moving the point (x, y) =(1,-2) to
the point $\left(x^{\prime}, y^{\prime}\right) =(0,0)$
equation in x y coordinates?

• A) \(\frac{x^{2}}{16}+\frac{y^{2}}{9}=1\)
• B) \(\frac{(x+1)^{2}}{16}+\frac{(y-2)^{2}}{9}=1\)
• C) \(\frac{(x-1)^{2}}{16}+\frac{(y+2)^{2}}{9}=1\)
• D) \(\frac{\left(x^{\prime}-1\right)^{2}}{16}+\frac{\left(y^{\prime}+2\right)^{2}}{9}=1\)

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