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The Following MINITAB Output Presents a 95% Confidence Interval Find the Sample Size Needed So That The

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The following MINITAB output presents a 95% confidence interval.
 The assumed sigma =10.5211 Variable N Mean  SE Mean 95%CIx5839.5011.3815(36.793,42.209) \begin{array}{ccccc}\hline {\text { The assumed sigma }=10.5211} & \\\text { Variable } & \mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} \\\mathrm{x} & 58 & 39.501 & 1.3815 & (36.793,42.209) \\\hline\end{array}

Find the sample size needed so that the 95%95 \% confidence interval will have a margin of err 1.2.


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