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The Following MINITAB Output Presents a Multiple Regression Equation y^=b0+b1x1+\hat { y } = b _ { 0 } + b _ { 1 } x _ { 1 } +

question 117

Multiple Choice

The following MINITAB output presents a multiple regression equation y^=b0+b1x1+\hat { y } = b _ { 0 } + b _ { 1 } x _ { 1 } + b2x2+b3x3+b4x4b _ { 2 } x _ { 2 } + b _ { 3 } x _ { 3 } + b _ { 4 } x _ { 4 }
The regression equation is
Y=5.5079+1.6552X11.1088X2+1.3981X31.2465X4\mathrm { Y } = 5.5079 + 1.6552 \mathrm { X } 1 - 1.1088 \mathrm { X } 2 + 1.3981 \mathrm { X } 3 - 1.2465 \mathrm { X } 4

 Predictor  Coef  SE Coef  T  P  Constant 5.50790.76401.10020.314 X1 1.65520.70323.19290.002 X2 1.10880.60233.23100.005 X3 1.39810.89701.81370.087 X4 1.24650.82511.14330.354\begin{array}{lllll}\text { Predictor } & \text { Coef } & \text { SE Coef } & \text { T } & \text { P } \\\text { Constant } & 5.5079 & 0.7640 & 1.1002 & 0.314 \\\text { X1 } & 1.6552 & 0.7032 & 3.1929 & 0.002 \\\text { X2 } & -1.1088 & 0.6023 & -3.2310 & 0.005 \\\text { X3 } & 1.3981 & 0.8970 & 1.8137 & 0.087 \\\text { X4 } & -1.2465 & 0.8251 & -1.1433 & 0.354\end{array}

S=2.2181RSq=41.6%RSq( adj ) =35.0%\mathrm{S}=2.2181 \quad \mathrm{R}-\mathrm{Sq}=41.6 \% \mathrm{R}-\mathrm{Sq}(\text { adj }) =35.0 \%

 Analysis of Variance  Source  DF  SS  MS  F P  Regression 4637.5159.47.14800.003 Residual Error 40893.222.3 Total 441530.7\begin{array}{l}\text { Analysis of Variance }\\\begin{array}{lcccrr}\text { Source } & \text { DF } & \text { SS } & \text { MS } & \text { F P } & \\\text { Regression } & 4 & 637.5 & 159.4 & 7.1480 & 0.003 \\\text { Residual Error } & 40 & 893.2 & 22.3 & & \\\text { Total } & 44 & 1530.7 & & & \\\hline\end{array}\end{array}

Let β1\beta _ { 1 } be the coefficient X1X _ { 1 } Test the hypothesis H0:β1=0H _ { 0 } : \beta _ { 1 } = 0 versus H1:β10H _ { 1 } : \beta 1 \neq 0 at the α=0.05 level. \alpha = 0.05 \text { level. } What do you conclude?


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