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The Following MINITAB Output Display Presents a 95% Confidence Interval

question 10

Multiple Choice

The following MINITAB output display presents a 95% confidence interval for the difference between two means.
$\begin{array} { r r r r c } & \mathrm { N } & \text { Mean } & \text { StDev } & \text { SE Mean } \\ \text { A } & 11 & 82.843 & 25.548 & 7.703 \\ \text { B } & 9 & 46.094 & 27.511 & 9.170 \end{array}$

Difference $= m u ( A ) - m u ( B )$
$The following MINITAB output display presents a 95% confidence interval for the difference between two means. \begin{array} { r r r r c } & \mathrm { N } & \text { Mean } & \text { StDev } & \text { SE Mean } \\ \text { A } & 11 & 82.843 & 25.548 & 7.703 \\ \text { B } & 9 & 46.094 & 27.511 & 9.170 \end{array} Difference = m u ( A ) - m u ( B ) What is the point estimate of \mu _ { 1 } - \mu _ { 2 } ? A) - 46.948 B) 36.749 C) 46.094 D) 17$

$The following MINITAB output display presents a 95% confidence interval for the difference between two means. \begin{array} { r r r r c } & \mathrm { N } & \text { Mean } & \text { StDev } & \text { SE Mean } \\ \text { A } & 11 & 82.843 & 25.548 & 7.703 \\ \text { B } & 9 & 46.094 & 27.511 & 9.170 \end{array} Difference = m u ( A ) - m u ( B ) What is the point estimate of \mu _ { 1 } - \mu _ { 2 } ? A) - 46.948 B) 36.749 C) 46.094 D) 17$

What is the point estimate of $\mu _ { 1 } - \mu _ { 2 }$ ?

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