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-A Ball Is Thrown Upward with an Initial Velocity h=4.9t2+42t+30\mathrm { h } = - 4.9 \mathrm { t } ^ { 2 } + 42 \mathrm { t } + 30

question 97

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-A ball is thrown upward with an initial velocity of 42 meters per second from a cliff that is 30 meters high. The height of the ball is given by the quadratic equation h=4.9t2+42t+30\mathrm { h } = - 4.9 \mathrm { t } ^ { 2 } + 42 \mathrm { t } + 30 where h\mathrm { h } is in meters and t\mathrm { t } is the time in seconds since the ball was thrown. Find the time it takes the ball to hit the ground. Round your answer to the nearest tenth of a second.


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