Add the Proper Constant to the Binomial So That the Resulting

question 230

Multiple Choice

Add the proper constant to the binomial so that the resulting trinomial is a perfect square trinomial. Then factor the
trinomial.
- $$x ^ { 2 } + \frac { 1 } { 6 } x$$

• A) \(x ^ { 2 } + \frac { 1 } { 6 } x + 144 = ( x + 12 ) ^ { 2 }\)
• B) \(x ^ { 2 } + \frac { 1 } { 6 } x + \frac { 1 } { 144 } = \left( x + \frac { 1 } { 12 } \right) ^ { 2 }\)
• C) \(x ^ { 2 } + \frac { 1 } { 6 } x + \frac { 1 } { 36 } = \left( x + \frac { 1 } { 6 } \right) ^ { 2 }\)
• D) \(x ^ { 2 } + \frac { 1 } { 6 } x + \frac { 1 } { 12 } = \left( x + \frac { 1 } { 6 } \right) ^ { 2 }\)

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