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Find the Vertex of the Graph of the Quadratic Function f(x)=12x2+4x+152f ( x ) = \frac { 1 } { 2 } x ^ { 2 } + 4 x + \frac { 15 } { 2 }

question 53

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Find the vertex of the graph of the quadratic function. Find any intercepts and graph the function.
- f(x) =12x2+4x+152f ( x ) = \frac { 1 } { 2 } x ^ { 2 } + 4 x + \frac { 15 } { 2 }
 Find the vertex of the graph of the quadratic function. Find any intercepts and graph the function. - f ( x )  = \frac { 1 } { 2 } x ^ { 2 } + 4 x + \frac { 15 } { 2 }    A)  Vertex:  \left( - 4 , - \frac { 1 } { 2 } \right)    x -intercepts:  ( - 5,0 )   and  ( - 3,0 )  ;  y -intercept:  \left( 0 , \frac { 15 } { 2 } \right)     B)  Vertex:  \left( 4 , \frac { 1 } { 2 } \right)  ;  x -intercepts:  ( 5,0 )   and  ( 3,0 )  ;  y -intercept:  \left( 0 , - \frac { 15 } { 2 } \right)     C)  Vertex:  \left( 4 , - \frac { 1 } { 2 } \right)    x -intercepts:  ( 5,0 )   and  ( 3,0 )  ;  y -intercept  \left( 0 , \frac { 15 } { 2 } \right)     D)  Vertex:  \left( - 4 , \frac { 1 } { 2 } \right)    x -intercepts:  ( - 5,0 )   and  ( - 3,0 )  ;  y \text {-intercept: }\left(0,-\frac{15}{2}\right)

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