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Sketch the Graph of the Equation x=4y232y67x=-4 y^{2}-32 y-67 A)  vertex (3,4)\text { vertex } ( 3,4 )

question 113

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Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center andradius.
x=4y232y67x=-4 y^{2}-32 y-67
 Sketch the graph of the equation. If the graph is a parabola, find its vertex. If the graph is a circle, find its center andradius.  x=-4 y^{2}-32 y-67    A)   \text { vertex } ( 3,4 )      B)   \text { vertex } ( - 4 , - 3 )      C)   \text { vertex } ( - 3 , - 4 )      D)   \text { vertex } ( - 3,4 )


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