The Graph of the Equation Is a Circle $x^{2}+y^{2}+6 x+6 y+14=0$

question 84

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $x^{2}+y^{2}+6 x+6 y+14=0$

• A) center \(( - 3,3 )\); radius \(= 2\)
• B) center \(( 3,3 )\); radius \(= 2\)
• C) center \(( 3 , - 3 )\); radius \(= 2\)
• D) center \(( - 3 , - 3 )\); radius \(= 2\)

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