The Graph of the Equation Is a Circle $x^{2}+2 x+y^{2}-4 y-19=0$

question 64

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $x^{2}+2 x+y^{2}-4 y-19=0$

• A) center \(( 1,2 ) ;\) radius \(= 2 \sqrt { 6 }\)
• B) center \(( 1 , - 2 )\); radius \(= 2 \sqrt { 6 }\)
• C) center \(( - 1,2 )\); radius \(= 2 \sqrt { 6 }\)
• D) center \(( - 1,2 )\); radius \(= 24\)

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