The Graph of the Equation Is a Circle $(x+4)^{2}+(y+1)^{2}=16$ A) Center $( 4 , - 1 )$

question 95

Multiple Choice

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $(x+4) ^{2}+(y+1) ^{2}=16$

• A) center \(( 4 , - 1 )\); radius \(= 4\)
• B) center \(( - 4,1 )\); radius \(= 4\)
• C) center \(( 4,1 )\); radius \(= 4\)
• D) center \(( - 4 , - 1 )\); radius \(= 4\)