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Here Is a Sample Proof That Contains an Error aba \mid b

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Short Answer

Here is a sample proof that contains an error. Explain why the proof is not correct. Theorem: If aba \mid b and bcb \mid c , then aca \mid c . Proof: Since ab,b=aka \mid b , b = a k .
Since bc,c=bkb \mid c , c = b k .
Therefore c=bk=(ak)k=ak2c = b k = ( a k ) k = a k ^ { 2 } .
Therefore aca \mid c .


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