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If f(w,x,y,z)=(xˉ+yzˉ)+(wˉx)f ( w , x , y , z ) = \overline { ( \bar { x } + y \bar { z } ) } + ( \bar { w } x )

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If f(w,x,y,z)=(xˉ+yzˉ)+(wˉx)f ( w , x , y , z ) = \overline { ( \bar { x } + y \bar { z } ) } + ( \bar { w } x ) , find f(0,1,0,1)f ( 0,1,0,1 )


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