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Solve the Equation log2x+3+log2x=1\log _ { 2 } \sqrt { x + 3 } + \log _ { 2 } \sqrt { x } = 1

question 7

Multiple Choice

Solve the equation.
- log2x+3+log2x=1\log _ { 2 } \sqrt { x + 3 } + \log _ { 2 } \sqrt { x } = 1


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