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Solve the Problem logb20.333\log _ { b } 2 \approx 0.333

question 68

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Solve the problem.
-Use logb20.333\log _ { b } 2 \approx 0.333 and logb60.862\log _ { b } 6 \approx 0.862 to approximate the value of the given logarithm. logb12\log _ { b } 12


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