Solve the Equation by Using the Quadratic Formula $$6 y + 3 = - 4 y ^ { 2 }$$

question 149

Multiple Choice

Solve the equation by using the quadratic formula.
- $$6 y + 3 = - 4 y ^ { 2 }$$

• A) \(\left\{ - \frac { 3 } { 4 } + \frac { i \sqrt { 3 } } { 4 } , - \frac { 3 } { 4 } - \frac { i \sqrt { 3 } } { 4 } \right\}\)
• B) \(\left\{ - \frac { 9 } { 2 } , \frac { 1 } { 3 } \right\}\)
• C) \(\left\{ - \frac { 1 } { 4 } + \frac { \sqrt { 105 } } { 12 } , - \frac { 1 } { 4 } - \frac { \sqrt { 105 } } { 12 } \right\}\)
• D) \(\{ 2 + \sqrt { 3 } , 2 - \sqrt { 3 } \}\)

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Definitions:

Degrees of Freedom

The number of independent values or quantities that can vary in the calculation of a statistic, often affecting its distribution.

Confidence Interval

A scope of values, extracted from sample studies, that is likely to enclose the value of an unknown characteristic of the population.

T-Distribution

A statistical distribution used when estimating population parameters of a normally distributed population in situations where the sample size is small and the population standard deviation is unknown.

Degrees of Freedom

The count of separate values or amounts assignable to a statistical distribution.