Factor Completely Using the Trial and Error Method to Factor $8 z ^ { 2 } + 6 z - 9$

question 22

Multiple Choice

Factor completely using the trial and error method to factor trinomials. If unfactorable, indicate that the polynomial is
prime.
- $8 z ^ { 2 } + 6 z - 9$

• A) \(( 4 z - 3 ) ( 2 z + 3 )\)
• B) \(( 4 z + 3 ) ( 2 z - 3 )\)
• C) prime
• D) \(( 8 \mathrm { z } - 3 ) ( \mathrm { z } + 3 )\)

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Definitions:

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