Factor Completely Using the Grouping Method to Factor Trinomials $x ^ { 4 } - 4 x ^ { 3 } - 21 x ^ { 2 }$

question 97

Multiple Choice

Factor completely using the grouping method to factor trinomials. If unfactorable, indicate that the polynomial is prime.
- $x ^ { 4 } - 4 x ^ { 3 } - 21 x ^ { 2 }$

• A) \(x ^ { 2 } ( x + 3 ) ( x - 7 )\)
• B) \(x ^ { 2 } ( x - 3 ) ( x - 7 )\)
• C) \(x ^ { 3 } \left( x ^ { 2 } - 4 x - 21 \right)\)
• D) \(x ^ { 2 } ( x + 3 ) ( x + 7 )\)

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