Factor Completely $36 \mathrm { k } ^ { 2 } - 49 \mathrm {~m} ^ { 2 }$

question 89

Multiple Choice

Factor completely. If unfactorable, indicate that the polynomial is prime.
- $36 \mathrm { k } ^ { 2 } - 49 \mathrm {~m} ^ { 2 }$

• A) \(( 6 \mathrm { k } + 7 \mathrm {~m} ) ^ { 2 }\)
• B) prime
• C) \(( 6 \mathrm { k } + 7 \mathrm {~m} ) ( 6 \mathrm { k } - 7 \mathrm {~m} )\)
• D) \(( 6 k - 7 m ) ^ { 2 }\)

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