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The Vertex of a Parabola Occurs Where the Derivative of Its

question 183

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The vertex of a parabola occurs where the derivative of its equation is 0, so an equation associated with the equation of a
parabola can be solved to find the x-coordinate of the vertex. Find the vertex of the parabola, given the equation of the
parabola and its associated equation.
-Between x=8x = - 8 and x=1x = - 1 , the largest value of the expression y=x3+12x2+36x+9y = x ^ { 3 } + 12 x ^ { 2 } + 36 x + 9 occurs where 3x2+24x+36=03 x ^ { 2 } + 24 x + 36 = 0 . Of the values of xx that satisfy 3x2+24x+36=03 x ^ { 2 } + 24 x + 36 = 0 , which gives the maximum value of y=x3+12x2+36x+9?y = x ^ { 3 } + 12 x ^ { 2 } + 36 x + 9 ?


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