One Solution of a Polynomial Equation Is Given $$6 x ^ { 3 } + 16 x ^ { 2 } + 6 x - 4 = 0 ; - 1$$

question 162

Multiple Choice

One solution of a polynomial equation is given. Use synthetic division to find any remaining solutions.
- $$6 x ^ { 3 } + 16 x ^ { 2 } + 6 x - 4 = 0 ; - 1$$

• A) \(\frac { 1 } { 3 } , 2\)
• B) \(\frac { 1 } { 3 } , \frac { 1 } { 3 }\)
• C) \(- 2 , \frac { 1 } { 3 }\)
• D) \(\pm \frac { 1 } { 3 }\)

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