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A Certain Noise Measures 79 Decibels L=10log(II0)\mathrm { L } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)

question 196

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A certain noise measures 79 decibels. If the intensity is multiplied by 10, how many decibels will the new noise measure? L=10log(II0) \mathrm { L } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)


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