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The Number of Periods Needed to Double an Investment When n=ln2ln1.01\mathrm { n } = \frac { \ln 2 } { \ln 1.01 }

question 25

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The number of periods needed to double an investment when a lump sum is invested at 2%, compounded semiannually, is given by n n=ln2ln1.01\mathrm { n } = \frac { \ln 2 } { \ln 1.01 } . Find the number of years before the investment doubles in value, to the
Nearest tenth of a year.

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